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Solve the following proportion: 4/a+4=a/8
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I cross multiply first, right? @ganeshie8
\(\large \dfrac{4}{a} + 4 = \dfrac{a}{8}\)
like this ?
no, a+4 is under the 4 \[\frac{ 4 }{ a+4 }=\frac{ a }{ 8 }\]
Good :) then you're right ! yes you cross multiply first
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\[\frac{ a(a+4) }{ 32 }\] \[\frac{ a^2+4a}{ 32 }\]
a(a + 4) = (8)(4) a^2 + 4a = 32 continue...
do I factor out the numerator, i think that's what it's called. (top)
a^2 + 4a - 32 = 0 I believe your gonna have to use quadratic formula
wait....I think you can factor that (a + 8)(a - 4) = 0
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ooooh ok, now I remember! Yea, like that. The answers are: a=-8 & a=4
yep...thats what I got
Yaaaaay!! I solved the next one, I just want to make sure it's correct.
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