Does anyone understand Trigonometric ratios and how to use them to solve for the angle measures and lengths of sides in a right triangle?
Yea
Can you help me?
I can try, whats the question?
In JKL solve for X. Triangle JKL where angle K is a right angle. KL measures 34. JL measures x. Angle L measures 27 degrees.
I don't just want the answer I need some help understanding the whole process to get to the answer.
Ok, gimme a sec to draw it out and figure it out
ok
|dw:1398085986968:dw| is this what it looks like? If you have a picture
Yes
ok, well i was taught to use "sohcahtoa", if you dont understand, ill explain.
I understand sohcahtoa, I just don't know what to do to find the length of the sides. When ever I put it into my calculator it comes up with a strange number that could never be the length
If you're calculator is in Radian mode instead of Degrees, you're going to get a wrong answer. Is it a multiple choice or open response?
It is in degrees and the question is multiple choice.
I know that the ratio that i am using is cosine
the choices are74.89 30.29 38.16 66.73
|dw:1398086396122:dw|Is 38.2 or 38.16 on there, or something like that?
yes
38.16 : The answer
how do you find the cosine 27?
you do cosine of the angle
when I put cosine then 27 into my calculator it gives me 0.8910065
34/0.8910065=38.1590993
Wait! Now i get it! Thanks!
But how do you find the measurement of an angle?
I am trying to find the measure of angle P
just a second!
its not letting me view it
P to Q is 33.8 and the hypotenuse is 57.6 and angle P is right above the right angle
can you draw it out?
|dw:1398086982940:dw|
the comma is a point
multiple choice?
Yes 30.4° 59.6° 35.9° 54.1°
54.1
Do you wannna know how to get the answer?
Well, you have to use the inverse cosine, leaving class now, glad I could help you out! :)
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