Question

Factor 9x 6 – 16y 6 completely.

Answer 1

this doesn't make sense

Answer 2

9x^6 - 16y^6

Answer 3

ah there you go

Answer 4

(3x^6 -4y^3)(3x^6 +4y^3)

Answer 5

\[(3x^{6}-4y^{3})(3x ^{6}+4y ^{3})\]

Answer 6

9x^6 – 16y^6 =

Answer 7

my equation is your answer

Answer 8

ohhhh, Thanks

Answer 9

multiply it out and you'll see

Answer 10

ok

Answer 11

can you help me with this? Factor x^4 + x y^3 + x^3 + y^3 completely. Show your work. Hint: First factor out a monomial.

Answer 12

The formula for difference of squares is \(a^2 - b^2 = (a + b)(a - b)\)
In this case \(9x^6 - 16y^6 = (3x^3 - 4y^3)(3x^3 + 4y^3)\)
Check:
\((3x^3 - 4y^3)(3x^3 + 4y^3) = (3x^3(3x^3 + 4y^3) - 4y^3(3x^3 + 4y^3)\)

\(=(9x^6 + 12x^3y^3 - 12x^3y^3 - 16y^6)\)

\(=9x^6 - 16y^6\)