Integral help?? Pretty please? :)
For -1 ≤ x ≤ 1, F(x) = the integral from -1 to x for sqrt(1 - t^2) dt
What does F(1) represent geometrically? Evaluate F(1) and find F'(x). Thanks for any help!
I can find F'(x) and evaluate F(1) but I don't know what F(1) represents geometrically.
i think substitution method will help put t= cos(theta) first
To find F'(x) ?
I haven't learned about trig substitution yet...
How can I get the answer without that?
i dont know
Okay. Can you help with the first question? What does f(1) mean geometrically?
in order to determine f(1) geometrically we need to know what is f(x) first
i feel something wrong as x is going from -1 to 1 and t is going from -1 to x (which is not possible as per the problem)
Okay thanks for trying. :)
f(1) represents a point on the function at x=1 f' represents the slope of the tangent line to the function at a given x value
integral ... F(x), the integral of f(t) represents the area under the curve f(t) from 0 to x
F(1) defines a limit along the interval an endpoint to contain the area within.
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