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2 cos x √3 = 0 for trigonometry
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Notation does not makes sense. Did you mean \(2\cos(x) - \sqrt{3} = 0\)
If as presented, note that cos x = 0 when x = pi/2, 3 pi/2 etc.
Sorry it is 2 cos x + √3=0
So cos x = -sqrt(3)/2 and it looks related to a 30-60-90 triangle except for that minus sign. x = arc cos [-sqrt(3)/2], but perhaps they want you to find the actual angle x.
There isn't a minus sign that's radical 3
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?
Maybe they are referring to \[A \cos (Bx+c)\]?
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