1. y = x + 6
y = 2x (1 point)
(6, 12)
(–12, –6)
(–6, –12)
(2, 4)
2. 3x + 2y = 7
–3x + 11 = y (1 point)
(6, –3)
(6, –7)

(5, –4)
3. 2x – y = –7
4x – y = –4
(–1.5, 4)
(1.5, 10)
(4, –1.5)
(–1.5, –2)
For questions 4–5, how many solutions does the system have?

4. –4y + 4 = x
2x + 8y = 8
one solution
two solutions
infinitely many solutions
no solution
5. 6x + 2 = y
3y – 18x = 12
one solution
two solutions
infinitely many solutions
no solution

Question

1.   y = x + 6
y = 2x  (1 point)
(6, 12)
(–12, –6)
(–6, –12)
(2, 4)
2.     3x + 2y = 7
–3x + 11 = y  (1 point)
(6, –3)
(6, –7)

(5, –4)
3.   2x – y = –7
4x – y = –4  
(–1.5, 4)
(1.5, 10)
(4, –1.5)
(–1.5, –2)
For questions 4–5, how many solutions does the system have?

4.   –4y + 4 = x
2x + 8y = 8  
one solution
two solutions
infinitely many solutions
no solution
5.   6x + 2 = y
3y – 18x = 12  
one solution
two solutions
infinitely many solutions
no solution

anonymous · Answer

Help, I need the answers for these ASAP, I am terrible at algebra and math in general... I'm with connections, so anyone who's taken this before, it is lesson 2 unit 6 of connections academy Algebra 1 foundations A

anonymous · Answer

5 has 1 solution

anonymous · Answer

Thanks but do you know any of the others?

anonymous · Answer

4 has infinite many solution

anonymous · Answer

how about 2 and 3? are you from connections?

anonymous · Answer

what is question i unable to understand 
can you give me information

anonymous · Answer

I just don't understand what they mean by the sets that they're getting from an equation...How do you get a set from an unsolved equation? like are you supposed to solve the equation first but if you do that then how are you supposed to answer with a set?