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Mathematics 25 Online
OpenStudy (anonymous):

Can someone tell me these properties of exponents?

OpenStudy (anonymous):

1. Peter did simplify his work correctly but not completely. His answer should be x^12. His work would not be the same if he had to simplify x^3 + x^3 + x^3 + x^3. It would be 4x^3. 2. Remove numerator: 3sqrtx^6 Convert to exponential form: x^6/3 Simplify exponent: x^2 3. Step 1: Make denominators the same (x^(2/3))/(x^(4/9) = (x^(6/9))/(x^(4/9)) Step 2: Simplify numerators x^2/9 Step 3: Convert to radical form index 9 sqrtx^2 4. (3sqrtx)^3 = x3/3 = x x^1/3 • x1/3 • x1/3 = x3/3 = x (1)/(x^-1) = x 11sqrt x^5 * x^4 * x^2 = x11/11 = x

OpenStudy (anonymous):

Are those questions?

OpenStudy (anonymous):

No, that's my work, I just dont know the properties that I used. @knsaunders

OpenStudy (anonymous):

are you doing flvs algebra 1?

OpenStudy (anonymous):

Flvs, but Algebra 2 @knsaunders

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