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Simplify: e^3ln(2x)+2ln(y^2)-4ln(2xy)
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does it help to know that \[e^{\ln(whatever)}=whatever\]?
Sort of, but what do you do with the numbers before the ln? Just multiply them by whatever?
2x^3-4ln(2x)
Am I correct to say that what you actually meant was the following: \[e ^{3\ln(2x) + 2\ln(y^{2}) - 4\ln(2xy)}\]
Yes, that is what I meant.
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(8x^3y^4) / (16x^4y^4) = 1/2x
then its 1/2x
Thank you both
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