Question

What is the solution to the following equation?

(x - 3)2 = 14

Answer 1

yes thank you

Answer 2

I guess this equation should be

\[(x-3)^2=14\]

\[x^2-6x+9=14\]

\[x^2-6x+9-14=0\]

\[x^2-6x-5=0\]

With Bhaskara

\[\boxed{\boxed{x_1=3+\sqrt{14}~~and~~x_2=3-\sqrt{14}}}\]

Answer 3

Ah, opps. Dexter may be right on this one. Didn't realize that the 2 was an exponent. Sorry.