write the equation of the line in slope-intercept form that is parallel to the given line and passes through the given point. y=8x+5 , (6,7)
Is (6,7) your answer? Or what?
thats part of the problem
Since the line in parallel to the line equation given the new line will have the same slope as the one give
No, (6,7) is not the answer. I usually just graph this..
Now since we now thw slope is 8 we can form the equation using the point given
@Kaylaaa Do you know what slope-intercept form is?
(y-y1)=m(x-x1)
Do you know where we go from here @Kaylaaa
Slope-intercept form is y - mx + b.
* y = mx + b
this is all just so confusing to me
If you want a PARALLEL line you MUST have the SAME slope.
But @greenlegodude57 I am showing her how to do it analytically
The slope is the 'mx' part.
I am teaching her so let me finish first
The slope in the first equation is 8, so you know that your second equation must have 8 for its slope also(So it can be parallel with the first equation).
And your second equation must cross through the point (6, 7)
Now @Kaylaaa we are going to be using the equation i gave. m=8 y1=7 and x1=6
The only thing that's going to change is the number at the end of the first equation to create your second equation.
so we get y-7=8(x-6)
now we can change it to slope intercept form
y = 8x - 33 will be your answer.
ohkay ..
wait which one is it ?
thank you (:
Oops my bad. It's y = 8x - 41
ignore what i just said what i origanally put is correct sorry for the confusion. 6times 8 is 48
y = 8x - 33 crosses through (5, 7) not (6, 7). So your answer is y = 8x - 41
the answer is y=8x-41
i graphed it to check my answer and it is absolutely correct
well thank you .! (:
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