Question

Look at this linear equation. 3x + 5y = 30
Which of the following equations can be used to solve for y in the linear equation above?


y = - 3/5x + 30



y = 3x + 6



y = -3/5 x + 6



y = 3/5 x + 30

Answer 1

can anyone show me how to do this?

Answer 2

Here how to solve the problem. You need to know the formula for this. Which is y=m(x+b)
3x+5y=30
-3x -3x
5y-3x+30 -----> Divide by 5
y= -3/5x+6

Answer 3

Point is to isolate y to be alone on the left hand side,

Start by doing the inverse of everything, 3x + 5y = 30 you're adding 3x, so subtract 3x from both sides,

5y = -3x + 30

You're multiplying by 5, the inver is division, divide both sides by 5,

5y = -3x + 30
/5 /5 /5

y = -3/5 + 6

Answer 4

inverse*

Answer 5

i see it now i hade to out the aquatiom into y=mx+b form?

Answer 6

Yes, as it's Y = mx + b