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Mathematics 7 Online
OpenStudy (anonymous):

please help! Add and simplify:http://curriculum.kcdistancelearning.com/courses/ALG1x-HS-FL11/b/Exams/9HW5/9HW5_q3.gif

OpenStudy (anonymous):

\[\frac{x+1}{x}+\frac{x-3}{3x}\] this is not "simplify" this is "add" \[\frac{x+3}{x}\times \frac{3}{3}+\frac{x-3}{3x}=\frac{3(x+1)+x-3}{3x}\]

OpenStudy (anonymous):

ok how would you simplify

OpenStudy (anonymous):

multiply out in the numerator combine like terms

OpenStudy (anonymous):

so it would be x^2+1 over 3x?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

\[\frac{3(x+1)+x-3}{3x}\] \[=\frac{3x+3+x-3}{3x}\] is the first step second step is to combine like terms

OpenStudy (anonymous):

3x+3 is 6x plus x is 6x^2 minus 3 is 3x^2

OpenStudy (anonymous):

how would you add 6x plus x?

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