g(4)=-14 g'(4)=-5
g(3)=-18 g'(3)=-3

The equation is probably a quadratic function, but is there a way to get it?

Question

g(4)=-14  g'(4)=-5
g(3)=-18  g'(3)=-3

The equation is probably a quadratic function, but is there a way to get it?

loser66 · Answer

to me, I will do something like this
the quadratic function has the form  g(x) = ax^2 +bx +c
                                                     g(2) = 4a + 2b  +c = -14
                                                     g(3) = 9a +3b +c = -18

loser66 · Answer

now, take derivative: g'(x) = 2ax +b
                                g'(2) = 4a + b = -5
                                g'(3) = 6a +b =  -3
 so that 2a = 2 therefore a =1 and b = -9

osanseviero · Answer

oh...thanks!

loser66 · Answer

you got it? still have to find c

osanseviero · Answer

Yep, but it is easy to find now :) thanks :) got it perfectly

osanseviero · Answer

c=0

osanseviero · Answer

Perfect :) thanks a lot

loser66 · Answer

:)

osanseviero · Answer

I got a problem related to this...do you think you could help me?

loser66 · Answer

not sure, if it is not over my head, I will