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cos(theta)= 1 when theta = n*pi, for n an integer...true or false
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n is an integer, so say n = 0 theta = n*pi would then equal what?
this was the exact question out of my trig book.
theta = n*pi = 0*pi = 0
So when theta = 0, what is cos(theta)
1
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if n = 1, then theta = n*pi = 1*pi = pi
if n = 1, then theta = pi if that's true, what is cos(theta)?
.1719
make sure you're in radian mode
i am...am i missing something?
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cos(pi) is not 0.1719
-1
so if theta = pi, then cos(theta) = -1
go back to the original statement, is it true?
yes
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but we've just shown that cos(theta) = -1
-1 is still an integer
but the original statement is cos(theta) = 1
where theta = n*pi
n is an integer
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aha
thank you... im an idiot
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