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can you tell the equation of the given line
she's correct
equation of the given line = y=5/2 and its slope = -a/b a=0(coef.. of x) b=1(coef.. of y) therefore slope = 0 line parallel to this also have same slope.. equation of that line = y-y1=slope(x-x1) y-(-1)=0(x-3) y+1=0 y=-1
So i was correct ? thanks :) so i have to find the slope then plug in the x&y values , along with slope into this equation ,y-y1=M(x-x1) , and solve for y?
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ya.....
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