I have five questions about geometry. Can someone sit down for about 30 minute and help me with each one?

Question

compassionate · Answer

Here is the first one. 

NOTE: This is an FLVS Practice Exam. These exams are meant to be studied, retaken and looked over to gain an understanding for my upcoming final.

anonymous · Answer

none

anonymous · Answer

rotating something will result and circular base. A square pyramid doesn't have a circular base

anonymous · Answer

will result *in* circular base

compassionate · Answer

Wouldn't a cone look like this. 

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When rotated?

anonymous · Answer

a cone isn't a square pyramid

compassionate · Answer

Okay.. .Next one.

accessdenied · Answer

I'm thinking we should write the expression for sine and cosine for that angle in terms of the sides.
sin = opposite / hypotenuse,  cos = adjacent / hypotenuse.
Then solve for z in each case (which is always hypotenuse).

accessdenied · Answer

As an example, for sine:
  sin 50 = opposite/hypotenuse = x / z    The x is at the far leg from the angle 50 degrees.
We could solve this like a proportion for z
  $ \dfrac{\sin 50^o}{1} = \dfrac{x}{z} $

compassionate · Answer

Sin(x) = opposite/hypotenuse 

Six(x) = x/z 

Sin(x) * z = x

compassionate · Answer

Wait, I found x on accident oops!

compassionate · Answer

Wait, is x or y the hypotenuse? This triangle is a bit confusing.

accessdenied · Answer

The hypotenuse is always on the opposite side of the right angle, so z is the hypotenuse.
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accessdenied · Answer

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