What is the equation in standard form of the line which passes through (−2, 6) and has a slope of −1?
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OpenStudy (pinksapphire):
Find the slope intercept form first.
OpenStudy (pinksapphire):
y=-1x+4
OpenStudy (anonymous):
i jus now found the answer but an you help me with another question
OpenStudy (pinksapphire):
Okay :)
OpenStudy (anonymous):
Find the average rate of change for the given function from x = 2 to x = 4.
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OpenStudy (anonymous):
OpenStudy (anonymous):
thats what im suppose to use
OpenStudy (pinksapphire):
Do you have the function?
OpenStudy (anonymous):
no thats all it gives me
OpenStudy (pinksapphire):
Never mind I don't need it...
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OpenStudy (pinksapphire):
Do you know what a rate of change is?
OpenStudy (anonymous):
no
OpenStudy (pinksapphire):
Watch this video and it might help: www.youtube.com/watch?v=AanhgTnasa0
OpenStudy (pinksapphire):
The rate of change is 2
OpenStudy (pinksapphire):
The change in y divided by the change in x.
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OpenStudy (anonymous):
ohh so how would i start it
OpenStudy (pinksapphire):
Do This:
y2-y1 divided by x2-x1
OpenStudy (pinksapphire):
y1=0
y2=4
x1=2
x2=4
OpenStudy (pinksapphire):
4-0 divided by 4-2 = 4/2 or 2/1 or 2
OpenStudy (anonymous):
i got 2
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OpenStudy (anonymous):
is that the answer
OpenStudy (anonymous):
these are my answer choices
−2
one-half
negative one half
2
OpenStudy (pinksapphire):
Yes, the answer is 2.
OpenStudy (anonymous):
okay can you help me with another question ill give you a medal
OpenStudy (pinksapphire):
Sure, no problem :)
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OpenStudy (anonymous):
Jack and Jill had 3 pails of water. Each trip up the hill, Jack and Jill obtained 3 more buckets of water. Which of the graphs below represents Jack and Jill's number of pails over time?
OpenStudy (anonymous):
OpenStudy (anonymous):
did you see it
OpenStudy (anonymous):
@PinkSapphire
OpenStudy (pinksapphire):
Which one do you think it is?
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OpenStudy (anonymous):
d
OpenStudy (pinksapphire):
Yes, the last graph is correct.
OpenStudy (anonymous):
can you tell me how
OpenStudy (anonymous):
and you help me out with aother question
OpenStudy (anonymous):
Given f(x) = the quantity of 5x plus 1, divided by 2 solve for f-1(8).
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OpenStudy (pinksapphire):
Is this the equation?
f(x)=5x+1/2
OpenStudy (anonymous):
yeah
OpenStudy (anonymous):
but i have to solve for f^-1 (8)
OpenStudy (pinksapphire):
I don't get what it's asking...
OpenStudy (anonymous):
Given f(x) = the quantity of 5x plus 1, divided by 2 solve for f-1(8).
3
7
10
20
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OpenStudy (pinksapphire):
I'm not sure if I ever learned this...
OpenStudy (anonymous):
okay but 1 more question
OpenStudy (pinksapphire):
Okay...
OpenStudy (anonymous):
Find the average rate of change for the given function from x = −3 to x = 1.
OpenStudy (pinksapphire):
First you look at the graph and go to x=-3 and go up until you touch the line.
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OpenStudy (pinksapphire):
And that would be your y value.
OpenStudy (pinksapphire):
So now you have (-3,1) to (1,5).
OpenStudy (anonymous):
so its 1
OpenStudy (pinksapphire):
|dw:1398385143295:dw|
OpenStudy (pinksapphire):
You're still not done...On the table look for the rate of change.
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OpenStudy (pinksapphire):
It's 4/4 but you can simplify it to 1
OpenStudy (anonymous):
theres 4 whichi think would make a 8 right
OpenStudy (anonymous):
oh so 4/4 is 1 so thats my answer right
OpenStudy (pinksapphire):
Yes, this is your rate of change.
OpenStudy (anonymous):
The attachment is the answer to the original posted problem.
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OpenStudy (pinksapphire):
I don't know how to define the rate of change for you so you should look it up.
OpenStudy (anonymous):
i will but thank you sooo much
OpenStudy (pinksapphire):
No problem :)
OpenStudy (anonymous):
and @robtobey thank you cuhz i picked the opposite of it
OpenStudy (anonymous):
@robtobey
i need help with this question can you help me
Given f(x) = the quantity of 5x plus 1, divided by 2 solve for f-1(8).
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OpenStudy (pinksapphire):
Wait, for the last question I did something wrong...
OpenStudy (pinksapphire):
Wait never mind...
OpenStudy (anonymous):
wait what are you talking about :(
OpenStudy (pinksapphire):
Sorry I thought I did something wrong on the last question.