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Eliminate the parameter. x = t2 + 1, y = t2 - 1
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solve t2 from first equation, plug it in second equation
Or you can subtract equation 2 from equation 1 x = t^2 + 1 y = t^2 - 1 --------- ??
so t^2=-1 @ganeshie8 and that would = 0... @jim_thompson5910
on the left side, you'll have x-y on the right you'll have (t^2 + 1)-(t^2 - 1) and the right side simplifies to t^2 - t^2 + 1 - (-1) = 0t^2 + 2 = 2
So you'll get x-y = 2 using the subtraction method
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i only have these answers... y = x + 2, x ≥ 1 y = x - 2, x ≥ 1 y = x2 - 2, x ≥ 1 y = x2 + 2, x ≥ 1
now solve x-y = 2 for y
oh duh im stupid :P so y=x-2
you're not stupid and yes, it's y=x-2
thank you c:
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you're welcome
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