Question

Another question about logs... Question attached in file. Help would be appreciated and medal will be given out if you can help.

Answer 1

@cwrw238

Answer 2

im thinking its log a-log b but im not sure

Answer 3

log(a)-log(b)

Answer 4

Proof-Let log a = m and log b = n
=> 10^m = a and 10^n = b

a/b = 10^m / 10^n = 10^(m-n)
=> log(a/b) = m-n

Now because m = log a and n = log b we get that log(a/b) = log a - log b
which was to be demonstrated.