How can I solve this? Pic below.

Question

anonymous · Answer

Here is the pic. Can you solve it for y?

yttrium · Answer

It is complex analysis, then? :)
Okay wait a bit.

anonymous · Answer

whoops! not for y for x. Sorry

amistre64 · Answer

use the quadratic formula ...

yttrium · Answer

First, check if it is factorable. Is it factorable or not? @testhelp

yttrium · Answer

Not completing the square?

anonymous · Answer

Is this right? Pic attached

amistre64 · Answer

what is b^2 -4ac?

yttrium · Answer

hmmmm, not actually sure @testhelp maybe you can show your solution, then :))

anonymous · Answer

@amistre64 Here I used the qudratic formula. Is this right?

anonymous · Answer

What do you think @Yttrium ? Pic attached

amistre64 · Answer

you keep posting stuff that can be typed on here and its just a pain to be switching back and forth between windows to try to keep things in line.

simply type out your work so that i can see if your doing things right, or just guessing.

anonymous · Answer

@amistre64 Sorry but I have no idea how to type that out on a regular keyboard. That's why I keep posting screen shots. Sorry.

anonymous · Answer

@amistre64 I'll check to see how I can type it out.

anonymous · Answer

@amistre64   
Problem:
6x^2-5x+4=0


This is what I got using the quadratic formula   x=5+i√71/12 , 5-i√71/12

Is it right?

amistre64 · Answer

5^2 - 4(6)(4)  is a start :)

amistre64 · Answer

the part under the sqrt .... the rest looks good and lets see if that 71 is good

what does 5^2-4(6)(4)  equal?

amistre64 · Answer

25 - 4(24)

25 - 4(20) -4(4)

25 - 80 - 16

25 - 86 - 10

15 - 86

71 looks good

anonymous · Answer

@amistre64  thanks!

amistre64 · Answer

youre welcome