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How many roots (real and complex) describe the given polynomial function?
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one way is try to find the roots.
@TurtleMuffin
Let's factor f(x). f(x) = x^3 + 16x = x(x^2 + 16). If f(x) = 0, then 0 = x(x^2+16). This means either x=0 or (x^2+16). x=0 is one root. However, x^2+16 is just like that parabola I described in the last problem! It never touches the x-axis, since the +16 shifts it upwards. So, that has two imaginary roots. Therefore, f(x) has two imaginary roots.
so two real roots one complex root?
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