Question

For the equation y=3cot2x I need to find 2 asymptotes and period. I got period = pi. Asymptote 1 = 0 and asymptote 2 = pi/2. Can someone please tell me if I am right or not?

Answer 1

@sidsiddhartha I tried doing this one, can you tell me if i did it right please?

Answer 2

firstly period of cotx=pi but for cot2x it will be pi/2

Answer 3

so it would just be x=pi/2 instead of 2x=pi?

Answer 4

i have this graph. do those lines mean that my two asymptotes could be pi/2 and -pi/2 or do they have to be completely different numbers?

Answer 5

in this case there is a vertical asymptotes, which occurs at plus or minus pi over 2

Answer 6

now i have a questn 4u
y-tanx what can u say about it's asymptotes

Answer 7

sorry y=tanx

Answer 8

would those be horizontal asymptotes?

Answer 9

y tends to infinity as x tends to +-(pi/3),+-3*(pi/2).....
and tanx tends to infinity as x tends to +-pi/2,+-(3*pi/2)....
so it will have infinite number of vertical asymptote