Question

2^2x + 2^(x + 2) - 32 = 0

how would you solve for x?

Answer 1

\[2^{2x}+2^22^x-32=0\]
2^2 is 4
then let u=2^x
you will notice all you have to is solve a quadratic

Answer 2

Do you understand what I'm asking you to do @swift_13 ?

Answer 3

why is it 2^2*2^x

Answer 4

\[2^{x+2}=2^x \cdot 2^2 \text{ By law of exponents}\]