How many ml of 10 percent acid should be added to pure acid to make 60 ml of 30 percent acid? Please explain answer.

Question

hero · Answer

If: 
x = mL of 10% acid
y = mL of pure acid

Then:
The Total mL of Acid is:  
x + y = 60

And:
The Total Percent mL of Acid is:
.10x + y = .30(60)

So solve this system for $x$ to find how much of the 10% acid you need to add:

     x + y = 60
.10x + y = 18

hero · Answer

Keep in mind that 100% = 100/100 = 1

beccab003 · Answer

So what is the final result?

hero · Answer

You have to solve the system to find out.

beccab003 · Answer

Will you tell me if I have the correct answer?

hero · Answer

It would be best for you to post your steps. You can use the draw button to write or you can just type them out.