3x-4y=9 -32+2y=9
What's your goal here?
i have to solve it by using systems of elimination
3x-4y=9 -3x+2y=9 this is the problem, right ? (Look at what you wrote) .
yes thats how i wrote it and it showed up like that
\(\LARGE\color{blue}{ \bf 3x-4y=9 }\) \(\LARGE\color{blue}{ \bf -3x+2y=9 }\) subtract the second equation from the first equation. \(\LARGE\color{blue}{ \bf 3x-4y=9 }\) \(\LARGE\color{blue}{ \bf -3x+2y=9 }\) \(\LARGE\color{blue}{ \bf \text{──────────} }\) \(\LARGE\color{blue}{ \bf 0x-6y=0 }\) \(\LARGE\color{blue}{ \bf -6y=0 }\) \(\LARGE\color{blue}{ \bf y=0 }\) can you solve for x from here ?
Note how the first term of each equation "disappears," after we intentionally tried to eliminate it. This process is "elimination by addition/subtraction. The resulting equation is in y only. Find y. Last, use either of the original equations to find x. Write your solution in the form (x,y).
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