question:: three of six vertices of a regular hexagon are chosen at random. the probability that the triangle formed by these vertices is equilateral is??
@mathmale
@satellite73
@whpalmer4
Let's just look at a picture. |dw:1398658171391:dw| If we're picking sides at random, what's the probability of our first choice falling on a corner that can make an equilateral triangle? It's 100%, since it's our first choice and any of the 6 can do that for us. What about the next choice?
|dw:1398658260122:dw| Now you can see after we have randomly chosen one corner, our next choice can only be one of the two places shown. And so we have a 2/5 probability of picking this, would you agree? Now after that, what will be our probability of picking the final corner?
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