Solve triangle ABC. (If an answer does not exist, enter DNE. Round your answers to one decimal place.) PLEASE HELP!! a = 67, c = 50, ∠C = 54° ∠A = ° ∠B = ° b =
What is your question? What are you looking for?
It is basally asking to solve for the triangle with the given information. with the angles make a triangle out of it and find the angles..but i need help with that
Well the sum of all internal angles is 180 degrees.For B lets use the formula B=180-(A+C)
After you solve that use the sine rule.b/sinB and so on
Do you know the Law of Sine?
isn't sin opposite over hypotnuse?
Well that's sine but not the Law of sine
\[\frac{ a }{ \sin(A) }=\frac{ b }{ \sin(B) }=\frac{ c }{ \sin(C) }\] Have you learned that?
yes
|dw:1398648682157:dw| not draw to scale
Ok so, we can use the law of Sine to solve for angle A Using the formula: \[\frac{ 50 }{ \sin(54) } = \frac{ 67 }{ \sin(C) }\] Now you have to solve for sin(C), do you know how to do this?
its the same way as shown above
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