(Someone help i'm completely clueless on this)Find the x-intercept(s) and the coordinates of the vertex for the parabola y=x^2-6x+5 . If there is more than one x-intercept, separate them with commas.

Question

anonymous · Answer

to find the x-intercepts, set y to 0 and then solve (for y-intercepts, x=0)

to find the vertex, use the formula x=-b/2a to to find the axis of symmetry (x value of the vertex) and when you get x, substitute in the original equation in the problem to get your y. Then your vertex is (x,y) <--- whatever you get

If it is not obvious, quadratic equations are in the form ax^2+bx+c, which is where you get b and a for x=-b/2a

pinksapphire · Answer

the x-intercepts are (5,0) and (1,0)

pinksapphire · Answer

x=3
y=-4

anonymous · Answer

I stuck trying to find the intercepts but I found out how and I checked with your answer thanks to both for helping.

pinksapphire · Answer

Okay :)