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Mathematics 27 Online
OpenStudy (anonymous):

Find the rule of the quadratic function whose graph has its vertex at (2, 1) and passes through (1, 4).

OpenStudy (jdoe0001):

have you covered parabolas yet?

OpenStudy (anonymous):

yes

OpenStudy (jdoe0001):

ok

OpenStudy (jdoe0001):

\(\bf y = a(x-{\color{blue}{ h}})^2+{\color{red}{ k}}\qquad vertex\ (2,1)\implies y = a(x-{\color{blue}{ 2}})^2+{\color{red}{ 1}}\) so what's "a"? we dunno, but we know that the parabola passes through (1,4) meaning that when x = 1, y = 4 thus \(\bf through \quad ({\color{green}{ 1, 4}})\quad y = a(x-{\color{blue}{ 2}})^2+{\color{red}{ 1}}\implies {\color{green}{ 1}} = a({\color{green}{ 2}}-{\color{blue}{ 2}})^2+{\color{red}{ 1}}\) solve for "a" to find the factor "a", then plug it into the equation

OpenStudy (anonymous):

can u please factor a

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