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(8,-2);3x-4y=7
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What's your question?
It says "Write an equation of the line containing the given point and parallel to the given line." I keep trying to figure these out, but I'm confused.
Alright, do you know the point-slope formula?
Yeah, y-y^1=m(x-x^1)
Right, now all you have to do is plug in all the information you have into the equation, and put it back into slope-intercept form. Given (8, -2) and m=3/4. Because the slope id parallel, meaning the same as the original equation.
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So would it be y-(-2)=3/4(x-8)?
Yes, now just simplify it and get it into \(y=mx+b\) and you'll be set :)
Okay, thank you so much! :)
You're welcome, and welcome to the site, hope you enjoy your time here. :)
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