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evaluate the double integral
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\[\int\limits_{0}^{\frac{ \pi }{ 4 }}\int\limits_{1}^{2} r \tan^{-1} (\tan \theta)dr d \theta \]
You're only integrating with respect to r for the first portion there. So tan-1(tan theta) is just a constant
\[\int\limits_{0}^{\pi/4} \tan^{-1} (\tan \theta) d \theta *\int\limits_{1}^{2}r dr\]
I did'nt get the d(theta)
Once you're there, if you have issues integrating the trig function, I'd just wolfram alpha it. I still use their integral calculators.
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http://integrals.wolfram.com/index.jsp?expr=tan%5E-1%28tanx%29&random=false
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