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A square with a side of 12 is increased to a side of 15. By how much is the diagonal increased by?
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use the pythagorean theorem to find the diagonal when it was 12 then when it's 15 then get their difference, that's how much the diagonal increased by
a diagonal is always \[\sqrt{2}\times side\]
....using the pythagorean theorum like jdoe said
@jdoe0001 I solved but I don't know what exactly is. 3 , right?
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hmmm, true.. you could just use the 3x3 square too
so it will be \[15\sqrt{2}-12\sqrt{2}\] i think... correct me if i am wrong @jdoe0001
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