Question

How do I factor this out and what are the zeros?

y=12x^2-4x+6x-2

Answer 1

,factor out 4 from first two terms 12x^2 - 4x & factor out 2 from 6x-2
What do you get ?

Answer 2

Is this right? 4x(3x-1)+2(3x-1)

Answer 3

Sorry
factor out 4x*

Answer 4

Yes correct !!

Answer 5

Now factor out common term again

Answer 6

How?

Answer 7

See we can factor out (3x - 1) .. right ?

Answer 8

Yes

Answer 9

So what do you get ?

Answer 10

For the zeros?

Answer 11

After factor out (3x-1)

Answer 12

-3?

Answer 13

no please check it after factor out we have (3x-1)*(4x+2) right ?

Answer 14

Can you show me how? Sorry, I started learning this in Algebra today so...

Answer 15

Now, I got it...I thought you had to do something else first.

Answer 16

How do I get the zeros though?

Answer 17

Okay we have 4x*(3x - 1) + 2*(3x - 1) then we factor out (3x - 1) from this
So we get (3x-1)(4x* 1 + 2* 1) that is (3x-1)*(4x+2)

Answer 18

to get zeros just equate this factor with zero
that is (3x - 1) * (4x - 2) = 0

Answer 19

Now use zero property ...

Answer 20

Can you show me how?

Answer 21

Zero property if (a) * (b) = 0 then (a)= 0 or (b) = 0

Answer 22

And then solve for x

Answer 23

Can you apply zero property ?

Answer 24

No :(

Answer 25

see we have (3x-1)*(4x +2) =0 so using that property we can write it as

(3x-1) = 0 or (4x+2) = 0 Okay ?

Answer 26

So it will be x=1/3 and 1/2

Answer 27

Please check sign of 1/2 ..

Answer 28

-1/2

Answer 29

Correct !!

Answer 30

Thanks!

Answer 31

You are most welcome :)