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Mathematics 18 Online
OpenStudy (anonymous):

log2(x+1)=3

OpenStudy (solomonzelman):

is 2 the base ?

OpenStudy (solomonzelman):

\(\LARGE\color{blue}{ \bf log_2(x+1)=3 }\) like this ?

OpenStudy (anonymous):

yes

OpenStudy (solomonzelman):

\(\LARGE\color{blue}{ \bf log_2(x+1)=3 }\) \(\LARGE\color{blue}{ \bf log_2(x+1)=3~log_22 }\) \(\LARGE\color{blue}{ \bf log_2(x+1)=log_22^3 }\) \(\LARGE\color{blue}{ \bf log_2(x+1)=log_28 }\) \(\LARGE\color{blue}{ \bf x+1=8 }\) \(\LARGE\color{blue}{ \bf x=7 }\)

OpenStudy (anonymous):

how about ln(x+3)=ln(2x)

OpenStudy (anonymous):

simple x+3 = 2x

OpenStudy (solomonzelman):

but what will you do to get that? one side of your problem is log, but the other is not. So I am just using a commpon approach of putting in the magic one, as log(base x) x. See what I am doing ?

OpenStudy (anonymous):

can you show me the work?

OpenStudy (solomonzelman):

I think I just did .

OpenStudy (anonymous):

but wht do i do after that

OpenStudy (solomonzelman):

after what ?!

OpenStudy (solomonzelman):

OMG, I am out ... !

OpenStudy (anonymous):

x+3-2x

OpenStudy (anonymous):

X+3= 2x 2x-x=3 x= 3

OpenStudy (anonymous):

how about 20e^3x=100

OpenStudy (anonymous):

divide both sides by 20 what du get?

OpenStudy (anonymous):

can u show me all work

OpenStudy (anonymous):

why dont you try?

OpenStudy (anonymous):

our teacher just gave us a exta credit sheet but didnt teach it to us told us to look it up

OpenStudy (anonymous):

so it wont tke much to try it qhy dont u divide both sides the left and the right side by 20

OpenStudy (anonymous):

okay so i get e^3x=5 then what

OpenStudy (anonymous):

take ln fr both sides

OpenStudy (anonymous):

so what would itlook like

OpenStudy (anonymous):

\[\ln(e^{3x})= \ln 5\] \[3x \ln e = \ln 5\] ln e = 1 so 3x = ln 5 solve for x

OpenStudy (anonymous):

can u please solve

OpenStudy (anonymous):

x = ln 5 / 3

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