Question

Derive the relation for the distance travelled in nth second

Answer 1

hi,
by the equation of motion, \[s=ut+1/2* at ^{2}\]
s(n) = un + 1/2* a* (n sqr)
s(n-1) = u(n-1) + 1/2* a (n-1)sqr
therefore s (nth) = s(n) - s(n-1)
by subtracting we get,
s nth= ut +1/2*a* (2n-1)
i hope it will help you.