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Integral help:
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\(f(x)=\sqrt{x}\) is strictly increasing right?
Right.
so on the interval \([4,16]\) what is its minimum value?
10?
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??
it is increasing the minimum is at the left endpoint, the maximum at the right
oooh i see you were including the 5, i was ignoring it yes, 10 is right, i mentally pulled the 5 out of the integral but if you mean the min of \(5\sqrt{x}\) then 10 is right
similarly the max will be \(20\) use those numbers i forgot the 5, sorry
I tried both, didn't accept either.
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\[\int_4^{16} 5dx=12\times 5=60\] for the left
the right is \(12\times 20\)
Oh, I see, thank you :)
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