Differentiation ( I would be typing)
Suppose u and v are the functions of x that are differentiable at x = 0 and that u(0)= 5 U"(0)= -3 v(0) = -1 v"(0) = 2
well, i mean, yes you can find some u,v unimited avtually, but i'm assuming you'll need to use integration by parts based off of the terms
\[\frac{ d }{ dx }(7v - 2u)\]
ahh ok, is there more?
no i solved the rest equation tool wasn't working
\[\frac{ d }{ dx }7v - \frac{ d }{ dx } - 2u\]
Would be like that
why do you have two minuses?
Quotient rule?
well, I mean I assume you were given \(f'(x)=\frac{d}{dx}(7v-2u)\)
yeah
and you want to find all possible u,v or just the value of f(x) at 0?
f(x) =0 there is only one value in the answer booklet
k so(this is like a hidden easy question in all the mumbo jumbo) if I rephrase it like this, does it make it a little more clear:\[(\frac{d}{dx}) [f(x)] =(\frac{d}{dx})[7v-2u]\]
yes
so what is your f(x)? or more easily put, what is f( u(0),v(0) )?
I will first find deivative of 7v and then - 2u and then add them together
\[\frac{ d }{ dx }7v + \frac{ d }{ dx } -2u\]
Is that correct
you don't need to find any derivatives
you are way overcomplicating it
the function is given without any work
I got 20 as the answer i know derivatives are given but that's how u would represent
is 20 correct
for f(0)? I dis not get anywhere close to that
please show your work
7*2 + (-2*-3) =20
that is f" (double prime aka second derivative) by the values you gave me, and we want f correct?
LOL sry but i dindn't get what u said but i got 20 and saw the answers and it is correct!
..uhm you've had me doing the wrong problem this whole time then
Maybe using full sentences, posing the full question, and obeying some more rules of grammar would be useful next time.
also note 1st derivative uses one ' second uses two "
ok
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