Question

PLEASE HELP!!! solve for the variable

Answer 1

Lol wish i could but this is hard... atleast i tried xD

Answer 2

thanks any way

Answer 3

:/ sorry XD

Answer 4

I can say that √3/2 is the value of sin(60)

Answer 5

any help would be greatly appreciated!!!!!!!

Answer 6

\[2 \sin \theta \cos \theta=\sin 2 \theta\]

Answer 7

the part i don't understand is where it says give exact answers

Answer 8

So indirectly question asks

\[\sin 2 \theta=\dfrac{\sqrt{3}}{2}\]

Answer 9

Theta=?

Answer 10

Hey I am here

Answer 11

i am still not sure... can i divide \[(\sqrt{3})/2\] by 2 again?

Answer 12

assume 2theta=k

sin k=root{3}/2

k=?

Answer 13

so k=root3 over 2 divided by sin?

Answer 14

Not really. You cant take sin away like that. Just remember that sin 60=root3/2

So 60=k=2theta

Then theta=?

Answer 15

so theta= root 3

Answer 16

60=2theta

then theta=?

Answer 17

hreeg97 when do you need this.

Answer 18

so then it should be 30?
and tomorrow

Answer 19

Yes :)

Answer 20

ok

Answer 21

THANK YOU SO MUCH!!!!!!!!!!!!!

Answer 22

yw :)

Answer 23

D: I was of no use!

Answer 24

sorry