A bag contains 24 blue marbles, 32 yellow marbles, 43 white marbles, and 21 red marbles.

If a marble is drawn from the bag and replaced 90 times, about how many times would a yellow marble be drawn?

Question

A bag contains 24 blue marbles, 32 yellow marbles, 43 white marbles, and 21 red marbles.
 
If a marble is drawn from the bag and replaced 90 times, about how many times would a yellow marble be drawn?

jim_thompson5910 · Answer

How many marbles are there total?

anonymous · Answer

120

jim_thompson5910 · Answer

what fraction of that 120 are just yellow?

anonymous · Answer

32/120

jim_thompson5910 · Answer

which reduces to ?

anonymous · Answer

4/15 ?

jim_thompson5910 · Answer

That's the probability of drawing a yellow marble

jim_thompson5910 · Answer

Multiply that probability by the number of trials (90) to get your final answer

anonymous · Answer

So I would have to convert the fraction to a decimal first right?

jim_thompson5910 · Answer

or you can multiply the fraction with 90

think of 90 as 90/1

jim_thompson5910 · Answer

then multiply straight across and reduce

anonymous · Answer

$$\frac{ 4 }{ 15} \frac{ 90 }{ 1 }    4\times90=360|15\times1=15| \frac{ 360 }{ 15 }?$$

anonymous · Answer

$$\frac{ 360 }{ 15 }$$ is an improper fraction though?

jim_thompson5910 · Answer

now reduce 360/15

anonymous · Answer

$$\frac{ 24 }{ 1 }$$

jim_thompson5910 · Answer

and that's the same as 24

jim_thompson5910 · Answer

so you'd expect about 24 marbles to be yellow (out of the 90)

jim_thompson5910 · Answer

and notice how 24/90 reduces to 4/15 which is the probability of choosing yellow

anonymous · Answer

Cool :D Thanks +Medal/Fan

jim_thompson5910 · Answer

you're welcome