Question

If the area of a rectangle 24a2b and the length is 8ab2, what would the width of the rectangle, given that width is found by dividing area by length? Simplify the answer.

the quantity of 3 times a all over b

b over the quantity 3 times a

3 over the quantity a times b

2st

Answer 1

Divide: 24(a^2)b / 8a(b^2) = 24/8 * a^2/a * b/b^2 = ?

Answer 2

is it \(A=24a^2b,\ and\ l=8ab^2\)?

if so, \(\LARGE w=\frac{A}{l}=\frac{24a^2b}{8ab^2}\)

remember the law of exponents \(\Large \frac{x^m}{x^n}=x^{m-n}\)

Answer 3

24a2b8ab2=248∗a2a∗bb2=?

Answer 4

3?

Answer 5

you cannot eliminate the variables

Answer 6

I know Iam redoing it to figure out where the variables go....

Answer 7

Ok so it would be A

Answer 8

@Chibi_Robo3

Answer 9

yep ;)

Answer 10

Thanks!