Mathematics
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OpenStudy (anonymous):
HELP MEEEE!
What is the center of the circle that has a diameter whose endpoints are (2, 7) and (-6, -1)?
(4, 3)
(-2, 4)
(-2, 3)
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OpenStudy (anonymous):
@jacob1233 ? want to help?
OpenStudy (anonymous):
@Jadeishere this one pretty please?
OpenStudy (anonymous):
sure lets see here...
OpenStudy (anonymous):
and this one... Find the distance between the points (-4, -5) and (3, -1).
OpenStudy (anonymous):
choices are \[\sqrt{65} or \sqrt{37} or \sqrt{17}\]
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OpenStudy (jadeishere):
Hold on i'm going to give you a formula to use real quick >.<
OpenStudy (anonymous):
kk
OpenStudy (jadeishere):
\[\frac{ x _{2} + x _{1}}{ 2 } and \frac{ y _{2} + y _{1} }{ 2 } = midpoints\]
OpenStudy (anonymous):
sorry I'm swamping you guys... just a little desperate right now!
Factor the following polynomial completely.
-x 2 y 2 + x 4 + 4y 2 - 4x 2
choices:
(x - 2)(x - 2)(x + y)(x - y)
(x + 2)(x + 2)(x + y)(x - y)
(x + 2)(x - 2)(x + y)(x - y)
OpenStudy (jadeishere):
Okay hold on, seriously. You're going to confuse yourself on which questions we're helping you with if you go too fast. One at a time, please
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OpenStudy (anonymous):
oops. sorry.
OpenStudy (anonymous):
your first answer for the first question is (4,3) i think
OpenStudy (jadeishere):
Yes, it is.. Did you use that formula?
OpenStudy (anonymous):
me? no i just had to think for a sec but the formula would help.. but i didn't use it
OpenStudy (jadeishere):
Lol okay
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OpenStudy (anonymous):
the formula was for which one? first question or second?
OpenStudy (anonymous):
the last question answer is
1st factor (x²):
= - x²y² + x⁴ + 4y² - 4x²
= x⁴ - 4x² + - x²y² + 4y²
= x²(x² - 4) - y²(x² - 4)
= (x² - y²)(x² - 4)
= (x + y)(x - y)(x + 2)(x - 2)
Answer: c. (x + 2)(x - 2)(x + y)(x - y)
OpenStudy (jadeishere):
First, the formula wouldn't help with the second. Th second you're supposed to use a pathagorean theorem so a^2 + b^2 = c^2.
i need a graphing tool...
OpenStudy (anonymous):
lol...
OpenStudy (jadeishere):
hold on i'll use a paper thingy
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OpenStudy (anonymous):
ok. you guys are winning serious brownie points right now.
OpenStudy (anonymous):
if you are ever in Grand Cayman, Cayman Islands hit me up
OpenStudy (anonymous):
hahaa, and i just dont really know what you are asking for the second question? and i will if im ever there
OpenStudy (jadeishere):
so the distance between (-4, -5) and (3, -1) is sqrt(65)
OpenStudy (jadeishere):
>.< Sorry i had to graph it
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OpenStudy (anonymous):
yea. that ^ no problem its fine
OpenStudy (jadeishere):
One of my goals is to travel around the world, not the big countries like France or Brazil, but all of the small ones that go unseen >.<
OpenStudy (anonymous):
then come to Grand Cayman.
OpenStudy (jadeishere):
That's what I meant, so there's a chance i'll go there >.<
OpenStudy (anonymous):
want to help me with another one? only a few more before we get my score
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OpenStudy (anonymous):
cool!
OpenStudy (jadeishere):
Okay >.<
OpenStudy (anonymous):
choices are:
-5n^9
-5n^4
5n^4
OpenStudy (anonymous):
okay
OpenStudy (jadeishere):
brb
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
Volleygirl is there a picture?
OpenStudy (anonymous):
of the problem? yes in the attached file
OpenStudy (anonymous):
okay sorry i didnt see it
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OpenStudy (anonymous):
no problem.
OpenStudy (jadeishere):
-5n^4
OpenStudy (anonymous):
yeah i think ur right
OpenStudy (jadeishere):
Lol >.<
OpenStudy (anonymous):
you 2 are amazing.
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OpenStudy (jadeishere):
Ha, funny >.< I'm merely good
OpenStudy (anonymous):
naaa ur to kind we are just here to help
OpenStudy (anonymous):
OpenStudy (anonymous):
ur amazing so hush
OpenStudy (jadeishere):
(60 sqrt3)
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OpenStudy (anonymous):
choices for this one are:
\[60\sqrt{5}...60\sqrt{3}... or... 50\sqrt{3}\]
OpenStudy (anonymous):
wow. ur fast
OpenStudy (jadeishere):
Lol xD When i try i can be
OpenStudy (anonymous):
dang it i had just got the answer too >_< lold
OpenStudy (jadeishere):
xD
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OpenStudy (anonymous):
only a few more questions till i get the grade! you guys are basically checking my work for me :D
OpenStudy (anonymous):
XD
OpenStudy (jadeishere):
checking? pish posh
OpenStudy (anonymous):
choices are:
1/4
-4
4
OpenStudy (anonymous):
i ended up with 1/4, but im pretty sure im wrong
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OpenStudy (jadeishere):
it's 4
OpenStudy (anonymous):
i got 4
OpenStudy (anonymous):
see what i mean?
OpenStudy (jadeishere):
Lol >.<
OpenStudy (anonymous):
lol XD
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OpenStudy (anonymous):
choices are:
19xsqrt3x
5xsqrt3x
13xsqrt3x
OpenStudy (jadeishere):
5x sqrt3x
OpenStudy (anonymous):
i got b
OpenStudy (anonymous):
thnx
OpenStudy (jadeishere):
yep >.<
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OpenStudy (anonymous):
sqrt8(sqrt2 - x) = 11
solve for x
OpenStudy (anonymous):
brb
OpenStudy (anonymous):
kk jacob
OpenStudy (jadeishere):
\[\sqrt{8}\sqrt{2 - 3}\]
OpenStudy (jadeishere):
is that what it?
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OpenStudy (anonymous):
no...
OpenStudy (jadeishere):
Okay then i don't understand
OpenStudy (jadeishere):
oh i just saw the = 11 /).<
OpenStudy (anonymous):
first option
OpenStudy (anonymous):
second option
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OpenStudy (jadeishere):
\[\sqrt{8} \sqrt{2 - x} = 11\]is that it?
OpenStudy (anonymous):
third option
OpenStudy (anonymous):
solving for X
OpenStudy (jadeishere):
I don't understand what t looks like in the beginning so i have no clue what to start with
OpenStudy (anonymous):
\[\sqrt{8}\left( \sqrt{2-x} \right)=11\]
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OpenStudy (anonymous):
thats the problem. have to solve for X
OpenStudy (jadeishere):
I honestly don't know O.O Sorry
OpenStudy (anonymous):
s'ok.
OpenStudy (anonymous):
\[(10x ^{6}+20x ^{4}-15x ^{2})\div 5x ^{2}\]
OpenStudy (anonymous):
i keep coming up with 3x^6
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OpenStudy (anonymous):
but its not the correct answer
OpenStudy (anonymous):
it has empty spaces to fill in. ?x^4 + ?x^? - ?
OpenStudy (anonymous):
question marks are what is missing.
OpenStudy (jadeishere):
Can you take a screen shot please? That made no sense the way you worded it
OpenStudy (anonymous):