Question

Write the equation of the line that is perpendicular to the line y = three halvesx + 4 and passes through the point (-6, 3).

y = three halvesx - 1

y = three halvesx + 3

y = -two thirdsx - 1

y = -two thirdsx + 3

Answer 1

y = 3/2x + 4
the slope of this line is 3/2.

A perpendicular line will have the negative reciprocal slope. All that means is " flip " the slope and change the sign. So the slope we need is -2/3 (see how I flipped the slope and changed the sign)

Now we will use y = mx + b
slope(m) = -2/3
(-6,3) x = -6 and y = 3
now we sub
3 = -2/3(-6) + b
3 = 4 + b
3 - 4 = b
-1 = b

so our perpendicular line will be : y = -2/3x - 1

Answer 2

any questions ?

Answer 3

thank you so much!

Answer 4

no problem...glad to help

Answer 5

btw how do you give a medal

Answer 6

click on best response by the person you want to give a medal to

Answer 7

thx again @texaschic101

Answer 8

anytime :)