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Mathematics 21 Online
OpenStudy (bruno102):

Help please! Will give medal! In how many ways can a teacher arrange 10 students in the front row if there are 60 total students?

OpenStudy (bruno102):

Order does not matter by the way, it is a combination not a permutation.

OpenStudy (anonymous):

It certainly sounds like you've already got the answer then, 60 combinations 10, or 7.5394*10^10. Of course, if order did matter it would be 2.7358*10^17.

OpenStudy (bruno102):

I am confused by the answer though. Why would it be 2.7358? and why is there exponents?

OpenStudy (anonymous):

You said order did not matter, so ignore the second answer that one used permutations. The only reason I'm using exponents is because 60! is gigantic even dividing 50!*10! does little to reduce the number (that is the definition of a combination, by the way). In non-scientific form the answer would be 75394027500 with 9 significant figures.

OpenStudy (bruno102):

Hmm still a bit confused but thanks.

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