Matt has $200 in his bank checking account. Each month he deposits $300 into his account. Matt is saving up for a used car that costs $4200. A. Look at the algebraic equations below. Which equation can be solved to find out the number of deposits Matt needs to accumulate more than $4200? (1 point) •200x + 300 4200. •300x + 200 4200. •200x + 300

Question

Matt has $200 in his bank checking account. Each month he deposits $300 into his account. Matt is saving up for a used car that costs $4200. A. Look at the algebraic equations below. Which equation can be solved to find out the number of deposits Matt needs to accumulate more than $4200? (1 point) •200x + 300 > 4200. •300x + 200 > 4200. •200x + 300 < 4200. •300x + 200 < 4200. B. Solve, using algebraic transformations, the equation that you chose for Part A. C. How many deposits does Matt need to accumulate more than $4200? Remember labels.

anonymous · Answer

uh, wrong section... maybe you'll have better luck in Math?

anonymous · Answer

ok @MelissaHolmes

anonymous · Answer

200 + 300 x > 4200  = answer b

anonymous · Answer

the answer is b, solving it 
300x > 4000
x > 13 1/3

therefore 14 deposits :)