WILL GIVE MEDALS 12. which is equivalent to 2x/x-7- x+7/x?
A. (x-7)/(x(x-7)
B.(x+7)/(x(x-7)
C.(x^2+49)/(x(x-7)
D.(x^2-49)/(x(x-7)

Question

WILL GIVE MEDALS 12. which is equivalent to 2x/x-7- x+7/x? 
A. (x-7)/(x(x-7)
B.(x+7)/(x(x-7)
C.(x^2+49)/(x(x-7)
D.(x^2-49)/(x(x-7)

anonymous · Answer

@campbell_st  can you help

campbell_st · Answer

well you need a common denominator 

which will be x(x - 7)

so the 1st it becomes 

$$\frac{2x \times x}{x(x -7)} - \frac{x \times (x - 7)}{x(x - 7)}$$

you'll need to simplify the numerator... 

my suggestion is 

distribute 

collect like terms 

then factor...

anonymous · Answer

so do i combine all the x's

campbell_st · Answer

like terms... means the 2 things that are x^2... you can subtract them...

anonymous · Answer

so i get $$\frac{ (x-7) }{ (x(x-7) }$$

campbell_st · Answer

oops... slight mistake 

$$\frac{2x \times x}{x(x -7)} - \frac{(x +7)(x -7)}{x(x - 7)}$$

which becomes 

$$\frac{2x^2}{x(x -7)} - \frac{x^2 - 49}{x(x - 7)}$$

which simplifies to 

$$\frac{x^2 + 49}{x(x -7)}$$

anonymous · Answer

oh ok got it