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Express as a single logarithm and simplify. log6 9 + log6 24.
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logb a + logb c = logb ac
b is base Here, Can you figure out the answer
\(\log_b(a) + \log_b(c) = \log_b(ac)\)
log6 (9) + log6 (24)= Log6 (216)?
Yep..!!
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That can be further written as log6 6^3 = 3
The \(\LaTeX\) code for logs: `\(\log_b(a) + \log_b(c) = \log_b(ac)\)`
Thank you :)
Hero, what is the code to show that line in the box? like how did you make it not look like latex?
@hero
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It won't allow me to post it on here, but I can message it to you or anyone else who wants to know.
please thanks:)
`\(this is a test\)`
neet tnx
You passed
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