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Help!!! will give medal
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OH yea I fogot to put divide
(x^2-4)/(x-8)/(x-2) basically equals (x^2-4)/{(x-8)*(x-2)}
that being said you can factor the top to be (x+2)(x-2)/(x-8)(x-2)
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the (x-2)s cancel out leaving behind (x+2)/(x-8)
cool thank you :)
\[\frac{x ^{2}-4 }{ (x-8)(x+2) }\]
\[\frac{ (x+2)(x-2) }{(x-8)(x+2)}\]
hmm ok so there is more
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=\[\frac{ (x+2) }{(x-8)}\]
llol no i was just trying to show it in equation form cuz sometimes the weird ^ stuff can be confusing
ok well thank you :)
Np :D
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