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Write in logarithmic form
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\[\huge E= \frac{ 1 }{ 2 }mv ^{2}\]
You can use the properties: log(ab)=log(a)+log(b) log((a)^m)=m log(a)
log(a/b)=log(a)-log(b)
Think:\[\ln [E= \frac{ 1 }{ 2 }mv ^{2}]\rightarrow ?\]
\[E = \dfrac{m}{2} v^2\] \[ \log E = \log \dfrac{m}{2} + 2 \log v\]
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Notice that m is just a constant, so this essentially is a straight line
y = \(\log E\) x = \(\log v\) \(y = \log \frac{m}{2} + 2 x\) straight line equation!
so we can split log m/2 as log m - log 2
you can
m and 2 are constants, so u can leave it as it is..
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thank you dude!
so logify ur data to straighten it :)
u wlc !
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