Question

(x+2)/(3x+3)times(x^2+4x+3)/(x-1)

Answer 1

First do (x^2+4x+3)/(x+1)
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Factor x^2+4x+3, and see if x+1 is a factor

Answer 2

\(\LARGE\color{blue}{ \bf \frac{(x+2)}{(3x+3)} \times \frac{(x^{2}+4x+3)}{(x-1)}= }\)


\(\LARGE\color{blue}{ \bf \frac{(x+2)(x^{2}+4x+3)}{(3x+3)(x-1)} = }\)


\(\LARGE\color{blue}{ \bf \frac{(x+2)(x+1)(x+3)}{3(x+1)(x-1)} }\)

Do you see what terms can you cancel out ?

Answer 3

yeah all the x's can cancel out

Answer 4

thank you soo much this helped a lot!!!

Answer 5

Well no:

The (x+1) cancel since (x+1)/(x+1) = 1

Answer 6

(x+1) cancels out, and nothing else.

Answer 7

ohh okay