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6=x+2y
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What are we solving?
are we solving for x?
im not sure it says to use x=0 and y=0
Oh so you have to find the intercepts, that's what I thought you had to do. Ok so all you have to do is set x = 0 to solve for y and set y = 0 to solve for x, does that make sense?
So lets say you want to solve for x, set y = 0 6 = x+2(0) x = 6 Now solve for y by setting x = 0.
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oh okay now i know what you mean
Alright :), so what did you get for y?
i got 3
6 = 0 +2y y = 6/2 = 3 good job!
thanks
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y=x+2 do i do the same thing
Depends on the question, but if it's asking you to find the intercepts, yup!
it just says practice graphing problems use the table of valued approach include an x=0 and y=0
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